In an a.p if sn n 4n + 1 find the a.p
WebSep 20, 2024 · Expert-Verified Answer 26 people found it helpful Wafabhatt given , Sn =n ( 4n + 1 ) = 4n^2 + n we know that, Tn = Sn - S (n-1) =4n^2+n -4 (n-1)^2 - (n-1) =4 (n^2-n^2+2n-1)+ (n-n+1) =8n - 4 + 1 = 8n -3 hence , Tn = 8n -3 T1 =8 (1)-3 =5 T2= 8 (2)-3 =13 so, AP is 5, 13 , 21 and so on Find Math textbook solutions? Class 7 Class 6 Class 5 Class 4 WebIn an AP, if Sₙ = n(4n + 1), find the AP. Solution: Given, the expression for the sum of the terms is Sₙ = n(4n + 1) We have to find the AP. Put n = 1, S₁ = 1(4(1) + 1) = 4 + 1 = 5. Put n …
In an a.p if sn n 4n + 1 find the a.p
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WebJan 22, 2024 · • A sequence is said to be in AP (Arithmetic Progression), if the difference between its consecutive terms are equal. • The nth term of an AP is given as ; T (n) = a + (n-1)•d , where a is the first term and d is the common difference. • The common difference of an AP is given as ; d = T (n) - T (n-1) WebJul 22, 2024 · What is Sn - Sn-1 in an AP Get the answers you need, now! mindhu203 mindhu203 22.07.2024 Math Secondary School answered What is Sn - Sn-1 in an AP See answer ... 4n + 2 Subtracting s(n-1) from S(n), T(n) = 4n - 2 OR Given a is first term and d be the common difference. Sn = (n/2)[ 2a + ( n -1) d]
WebApr 10, 2024 · The Indian Navy has released the official notification 1400 vacancies for the Indian Navy SSR Agniveer Exam 2024. The selection process includes a Computer Based Test, Written Exam & Physical Fitness Test (PFT), and last stage of Medical Examination. Candidates applying for the exam must check the Indian Navy SSR Agniveer Eligibility … WebFeb 5, 2024 · Find an answer to your question if the sum of n terms of an AP is given by Sn=n(4n+1),then find the nth term of the AP vishalsinghshiva vishalsinghshiva 05.02.2024
WebJun 24, 2024 · In an A.P., if Sn = n(4n + 1) then find the A.P. - YouTube 24. In an A.P., if Sn = n(4n + 1) then find the A.P.For Short Notes, Revision Notes And NCERT Solution.Visit...
WebMar 31, 2024 · If the sum of n terms of an A.P. is 2n^2 + 5n , then its nth term is A. 4n − 3 B. 3n − 4 C. 4n + 3 D. 3n + 4 asked Jul 16, 2024 in Arithmetic Progression by Maanas ( 26.0k points) arithmetic progression
WebSolution: The sum of n terms S n = 441 Similarly, S n-1 = 356 a = 13 d= n For an AP, S n = (n/2) [2a+ (n-1)d] Putting n = n-1 in above equation, l is the last term. It is also denoted by a n. The result obtained is: S n -S n-1 = a n So, 441-356 = a n a n = 85 = 13+ (n-1)d Since d=n, n (n-1) = 72 ⇒n 2 – n – 72= 0 Solving by factorization method, ons pay dateWebMar 29, 2024 · Similarly find the 3rd, the 10th and the nth terms. Given Sn = 4n – n2 Taking n = 1 S1 = 4 × 1−12 = 4 – 1 = 3 ∴ Sum of first term of AP is 3 Taking n = 2 in Sn S2 = … ons panningenWebJan 11, 2016 · IN an AP, if sn=n [4n+1] find the AP Asked by archita123 11 Jan, 2016, 06:12: PM Expert Answer Answered by 11 Jan, 2016, 06:22: PM Application Videos This … iogc websiteWebLet us assume that 301 is the n th term of AP. Then: T n = a + (n - 1)d. 301 = 7 + (n - 1) 4. 301 = 7 + 4n - 4. 301 = 4n + 3. 298 = 4n. n = 74.5. But 'n' must be an integer. Hence 301 cannot … ons paye rtiWebLet n = 1, then a (1) = S (1) - S (0) and S (n) = (n+1)/ (n+10) that implies S (1) = 2/11,S (0) = 1/10 but S (0) = Sum of first 0 terms which is equal to zero ( S (0) = 0 ) and that is a contradiction. So the formula a (n) = S (n) -S (n-1) works only for n > 1. ons pbzWeb^ r . c a l v i n McKi n n e y As the result of injuries received a week before, R. Calvin McKinney, a well known resident of near T aney town, died on Thursday morning. Mr. McKinney, who was in his eighty eighth year, sustained a brok en collarbone on Thursday of last week. He had been visiting his son, John McKinney, on the home farm and ... on space warfare: a space power doctrineWebGiven that sn = 4n^2 + 2n. ----- (1) Substitute n = 1 in (1), we get sn = 4(1)^2 + 2(1) = 4 + 2 = 6. So, Sum of the first term of AP is 6 i.e a = 6. Now, Substitute n = 2 in (1), we get sn = 4(2)^2 + 2(2) = 4 * 4 + 2 * 2 = 16 + 4 = 20. So, Sum of the first 2 terms = 20. Now, First-term + second term = 20 6 + a2 = 20 a2 = 20 - 6 a2 = 4. Hence in AP, ons paye reference number