WebApr 5, 2024 · Iron has a body-centred cubic unit cell with a cell edge of 286.65 pm. The density of iron is 7.87g cm –3. Use this information to calculate Avogadro’s number (At. mass of Fe = 56g mol –1 ). cbse class-12 1 Answer 0 votes answered Apr 5, 2024 by santoshjha (143k points) selected Apr 27, 2024 by Vikash Kumar The correct answer is WebThis is called a body-centered cubic (BCC) solid. Atoms in the corners of a BCC unit cell do not contact each other but contact the atom in the center. A BCC unit cell contains two atoms: one-eighth of an atom at each of the eight corners (8 × 1 8 1 8 = 1 atom from the corners) plus one atom from the center.
Answered: Calculate the density of metallic iron,… bartleby
WebAustenitic iron 3 Q Which of the following structures of iron has a body centered cubic space lattice A Ferrite 4 Q How many atoms are in the unit cell of a body centered tetragonal space lattice A Nine 5 Q How many atoms are in the unit cell of a close packed hexagonal space lattice A 17 total atoms 6 Q WebThe first three forms are observed at ordinary pressures. As molten iron cools past its freezing point of 1538 °C, it crystallizes into its δ allotrope, which has a body-centered cubic (bcc) crystal structure. As it cools further to 1394 °C, it changes to its γ-iron allotrope, a face-centered cubic (fcc) crystal structure, or austenite. At ... diana trout artist
Body Centered Cubic Unit Cell - Pearson
WebIron has a body centred cubic unit cell with the cell dimension of 286.65 pm. Density of iron is 7.87 g cm −3. Use this information to calculate Avogadro's number? (Atomic mass of … WebFeb 24, 2024 · The number of atoms in a cubic centimetre of Fe (Iron = 7.874g/cm³ ÷9.27 x 10²²grams = 8.494 × 10²¹atoms. In the question we are told Fe adopted a body centered cubic unit cell Hence , in Body centered cubic unit cell, we have: We have one atom at the 8 corners of a cube We also have one body atom the cube's center WebJul 4, 2024 · Calculate the density of metallic iron, which has a body-centered cubic unit cell (part (b) in Figure 12.5) with an edge length of 286.6 pm. Given: unit cell and edge length. Asked for: density. Strategy: Determine the number of iron atoms per unit cell. Calculate … citation x flight time